for(Edge* e = edges.head; e != nullptr; e = e->next_node)
        {
            Halfedge* h = e->halfedge;
            Vertex* v1 = h->from;
            Vertex* v2 = h->inv->from;
            Vertex* v3 = h->prev->from;
            Vertex* v4 = h->inv->prev->from;
            size_t d_Per = std::abs(static_cast<long>(v1->degree()-6)) + std::abs(static_cast<long>(v2->degree()-6)) + 
                           std::abs(static_cast<long>(v3->degree()-6)) + std::abs(static_cast<long>(v4->degree()-6));
            size_t d_Aft = std::abs(static_cast<long>(v1->degree()-7)) + std::abs(static_cast<long>(v2->degree()-5)) + 
                           std::abs(static_cast<long>(v3->degree()-7)) + std::abs(static_cast<long>(v4->degree()-5));
            if(d_Per > d_Aft)
            {
                flip_edge(e);
                printf("Flip successful: %zu\n", e->id);
            }
        }

这是我的边翻转的操作，为什么我翻转边也会卡死，没有理解，我前面的做法是定义了两个 set 类，分别存放要坍缩和分裂的，考虑到一次坍缩少三条边，我坍缩这么来写的：

for(Edge* e : selectedCollapseEdges)
        {
                printf("Attempting to collapse edge: %zu\n", e->id);
                if(selectedCollapseEdges.find(e->halfedge->next->edge) != selectedCollapseEdges.end())
                {
                    selectedCollapseEdges.erase(e->halfedge->next->edge);
                }
                if(selectedCollapseEdges.find(e->halfedge->inv->next->edge) != selectedCollapseEdges.end())
                {
                    selectedCollapseEdges.erase(e->halfedge->inv->next->edge);
                }                
                    collapse_edge(e);
                    
                printf("Collapse successful: %zu\n", e->id);
        }

这么写感觉怪怪的但是能运行过这一段
QQ 图片 20241119214110|690x258, 75%
这个是我翻转卡死的终端，我不知道是什么原因。 😩 😫 😩 😫

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